Referring to a Type with typeof

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Referring to a type with typeof

Another way to refer to the type of an expression is with typeof. The syntax of using of this keyword looks like sizeof, but the construct acts semantically like a type name defined with typedef.

There are two ways of writing the argument to typeof: with an expression, or with a type. The following is an example with an expression.

typeof (x[0](1))

This input assumes that ‘x’ is an array of functions; the type described is that of the values of the functions. The following is an example with a type name as the argument.

typeof (int *)

If you are writing a header file that must work when included in ANSI C programs, write __typeof__ instead of typeof. See Alternate keywords. A typeof-construct can be used anywhere a typedef name could be used. For example, you can use it in a declaration, in a cast, or inside of sizeof or typeof. In the following, the type described is that of pointers to int.

typeof (*x) y;

The following declaration uses ‘y’ as an array of such values.

typeof (*x) y[4];

The following declaration uses ‘y’ as an array of pointers to characters.

typeof (typeof (char *)[4]) y;

It is equivalent to the traditional C declaration,

char *y[4];

To see the meaning of the declaration using typeof, and why it might be a useful way to write, let’s rewrite it with the following macros.

#define pointer(T) typeof(T *) 
#define array(T, N) typeof(T [N])

Now the declaration can be rewritten the following way.

array (pointer (char), 4) y;

Thus,

array (pointer (char), 4)

is the type of arrays of 4 pointers to

char

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